(7x+x^2-12)(3x+5)=0

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Solution for (7x+x^2-12)(3x+5)=0 equation: 


Simplifying
(7x + x2 + -12)(3x + 5) = 0

Reorder the terms:
(-12 + 7x + x2)(3x + 5) = 0

Reorder the terms:
(-12 + 7x + x2)(5 + 3x) = 0

Multiply (-12 + 7x + x2) * (5 + 3x)
(-12(5 + 3x) + 7x * (5 + 3x) + x2(5 + 3x)) = 0
((5 * -12 + 3x * -12) + 7x * (5 + 3x) + x2(5 + 3x)) = 0
((-60 + -36x) + 7x * (5 + 3x) + x2(5 + 3x)) = 0
(-60 + -36x + (5 * 7x + 3x * 7x) + x2(5 + 3x)) = 0
(-60 + -36x + (35x + 21x2) + x2(5 + 3x)) = 0
(-60 + -36x + 35x + 21x2 + (5 * x2 + 3x * x2)) = 0
(-60 + -36x + 35x + 21x2 + (5x2 + 3x3)) = 0

Combine like terms: -36x + 35x = -1x
(-60 + -1x + 21x2 + 5x2 + 3x3) = 0

Combine like terms: 21x2 + 5x2 = 26x2
(-60 + -1x + 26x2 + 3x3) = 0

Solving
-60 + -1x + 26x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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